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Which equation represents a line that passes through (-9, -3) and has a slope of 6?
y-9= 6(x - 3)
y+9= 6x + 3)
y-3= 61X - 9)
y+ 3 = 6(x + 9)

Respuesta :

Answer:

[tex]\textup{\textbf{Option B}}[/tex]

Step-by-step explanation:

To solve this question we will go by the options, Let us start by substituting the point the graph passes through.

(i) [tex]$y - 9 = 6(x - 3)$\\[/tex]

We will Substitute the point [tex]$(-9,-3)$[/tex] to check if it satisfies the equation. Since, it does not we will move to the second equation.

We repeat this for the remaining three options.

For (iv) [tex]$y + 3 = 6(x  + 9)$[/tex]

substitute [tex]$x = -9$[/tex] and [tex]$y = -3$[/tex]

We get [tex]$ L.H.S. =  y + 3 = -3 + 3 = 0 $\\$ R.H.S. = 6(x + 9) = 6(-9 + 9) = 0$\\$ \therefore L.H.S. = R.H.S.$\\[/tex]

Now to verify for the slope, we rewrite the equation in the standard form [tex]$ viz., y = mx + c$[/tex] where [tex]$m$[/tex] is the slope of the given equation.

[tex]$ y + 3 = 6x + 54$\\$ \implies  y = 6x +54 - 3 = 6x +51$[/tex]

Comparing it with the standard form, we get the slope of the line to be equal to 6. Hence, Option 4 would be the correct answer.

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