Respuesta :
Answer:
One zero
Step-by-step explanation:
To find : number of zeroes at the end of product 458 · 885 .
It's given that when this number is written in ordinary decimal form, each 0 at its end comes from a factor of , or one factor of 2 and one factor of . g
First, we will find factors of 458 and 885 .
[tex]458=2\times 229\\885=3\times 5\times 59[/tex]
From this factorisation, we get
[tex]458\cdot 885=2\times 229\times 3\times 5\times 59[/tex]
i,e, [tex]458\cdot 885=2\times 3\times 5\times 59\times 229[/tex]
Here, we noticed that we have one 2 and one 5, which makes [tex]2\times 5=10[/tex]
So, we conclude that 458 · 885 ends at one zero .
