The measure of base angles of isosceles triangle having vertex angle as 80 degree is 50 degree each
Solution:
Given that,
In an isosceles triangle, the base angles are equal
Measure of vertex angle = [tex]=80^{\circ}[/tex]
Need to calculate two equal base angle of triangle
Lets measure of each of the base angle = [tex]=x^{\circ}[/tex]
So measured of three angles of triangle are [tex]\mathrm{x}^{\circ} \text { and } \mathrm{x}^{\circ} \text { and } 80^{\circ}[/tex]
And as the angles of a triangle add up to 180°
=> x+ x + 80 = 180
On solving above expression for x we get,
[tex]\begin{array}{l}{\Rightarrow 2 x+80=180} \\\\ {\Rightarrow 2x=180-80=100} \\\\ {\Rightarrow x=\frac{100}{2}=50}\end{array}[/tex]
Measure of base angle = x = 50 degree
Hence measure of base angles of isosceles triangle having vertex angle as 80 degree is 50 degree each
