Respuesta :
Answer:
The resistivity of the wire material is [tex]2.30\times10^{-8}\ \Omega-m[/tex]
Explanation:
Given that,
Length = 12.2 m
Width = 1.6 mm
Thickness = 0.11 mm
Voltage = 12.0
Current = 7.5 A
We need to calculate the resistivity of the wire material
Using formula of resistivity
[tex]\rho=\dfrac{RA}{l}[/tex]....(I)
Using ohm's law
[tex]R =\dfrac{V}{I}[/tex]
Put the value of R in equation (I)
[tex]\rho=\dfrac{VA}{lI}[/tex]
Put the value into the formula
[tex]\rho=\dfrac{12.0\times1.6\times10^{-3}\times0.11\times10^{-3}}{7.5\times12.2}[/tex]
[tex]\rho=2.30\times10^{-8}\ \Omega-m[/tex]
Hence, The resistivity of the wire material is [tex]2.30\times10^{-8}\ \Omega-m[/tex]
The resistivity of the wire material should be [tex]2.30 \times 10^{-8} \Omega -m[/tex]
Given information:
The wire has a total length of 12.2 m, a width of 1.6 mm, and a thickness of 0.11 mm. The wire is connected to the car's 12.0 V battery and draws 7.5 A.
Calculation of the resistivity of the wire:
[tex]= \frac{12\times 1.6\times 10^{-3}\times 0.11\times 10^{-3}}{7.5\times 1.22}[/tex]
= [tex]2.30 \times 10^{-8} \Omega -m[/tex]
Learn more about the wire here; https://brainly.com/question/14594037
