Answer:
[tex]g' = 12.11 m/s^2[/tex]
Explanation:
As we know that the acceleration due to gravity is given as
[tex]g = \frac{GM}{R^2}[/tex]
now for earth we know that
[tex]\frac{GM}{R^2} = 9.81 m/s^2[/tex]
now if on the surface of another planet we know that the mass is same as that the mass of Earth but radius is 10% less than the radius of Earth
so we have
[tex]r = 0.9 R[/tex]
so we will have
[tex]g' = \frac{GM}{(0.9R)^2}[/tex]
[tex]g' = \frac{GM}{0.81 R^2}[/tex]
[tex]g' = 1.23 \times 9.81[/tex]
[tex]g' = 12.11 m/s^2[/tex]
