Answer:
the specific heat capacity of the alloy in J/(g.K) is [tex]2.154[/tex]
Explanation:
Knowns
Final temperature [tex]T_{f}=31.1\°C[/tex], mass of water [tex]m_{w}=271g[/tex], specific heat capacity of water [tex]c_{w}=4.186J/g*\°C[/tex], initial temperature of water [tex]T_{w}=22.0\°C[/tex], mass of the alloy [tex]m_{A}=77.4g[/tex] and initial temperature of the alloy [tex]T_{A}=93.0\°C[/tex].
Applying Formula
We are going to use the following formula [tex]c_{A}=\frac{m_{w}c_{w}(T_{f}-T{w})}{m_{A}(T_{A}-T_{f})} =\frac{(271g)(4.186J/g*\°C)(31.1\°C-22.0\°C)}{77.4g(93.0\°C-31.1\°C)}=2.154J/g*\°C[/tex]
Finally in this case, as the specific heat capacity is measured grade per grade, conversion between Celsius and Kelvin is direct 1:1
