Answer:
Explanation:
Given
Initial mass 3 M
initial velocity u=3 m/s
3 M breaks into 2 M and M with velocity [tex]v_1[/tex] and [tex]v_2[/tex]
conserving momentum in x direction
[tex]3 M\times 3=2 M\times v_1\cos 30+M\times v_2\cos 45[/tex]-------------1
conserving Momentum in Y direction
[tex]0=2 M\times v_1\sin 30-M\times v_2\sin 45[/tex]
[tex]v_2=\sqrt{2}v_1[/tex]
substitute [tex]v_2[/tex] in 1
[tex]9 M=\sqrt{3}M v_1+M v_1[/tex]
[tex]v_1=\frac{9}{\sqrt{3}+1}=3.29 m/s[/tex]
[tex]v_2=\sqrt{2}v_1=4.65 m/s[/tex]
