[tex]x=\frac{12}{5}[/tex] or x= twelve-fifths
Option A is correct.
Step-by-step explanation:
We need to find the solution of:
[tex]\sqrt{x^2+49}=x+5[/tex]
Solving:
Taking square on both sides:
[tex](\sqrt{x^2+49})^2=(x+5)^2\\x^2+49=x^2+2(x)(5)+25\\Simplifying:\\x^2+49-x^2-10x-25=0\\-10x+24=0\\-10x=-24\\x=\frac{-24}{-10}\\ x=\frac{24}{10}\\x=\frac{12}{5}[/tex]
Verifying the solution by putting x = 12/5 in the given equation, we get true result.
So, [tex]x=\frac{12}{5}[/tex] or x= twelve-fifths
Option A is correct.
Keywords: Solving Square root Equations
Learn more about Solving Square root Equations at:
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brainly.com/question/4034547
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