Answer:
458ml
Explanation:
According to charles law, [tex]$\frac{V_{1}}{T_{1}} =\frac{V_{2}}{T_{2}} $[/tex]
Given values,
Volume occupied [tex]$V_{2}=500ml$[/tex]
Temperature [tex]$T_{1}=25.0^{\circ}C=25+273=298K$[/tex]
Second temperature [tex]$T_{2}=0.0^{\circ}C=273K$[/tex]
Volume [tex]$V_{2}=?$[/tex]
From charles law, [tex]$V_{2}=\frac{V_{1} \times T_{2}}{T_{1}}$ \\$=\frac{500 \times 273}{298}$\\$=458ml$[/tex]
[tex]$\therefore$[/tex] Volume occupied by the oxygen at 0.0°C is 458ml
