Answer:
[tex]\large\boxed{\dfrac{2150}{31}\approx69.35}[/tex]
Step-by-step explanation:
[tex]\bold{METHOD\ 1:}\\\\\begin{array}{ccc}43&-&62\%\\\\x&-&100\%\end{array}\qquad\text{cross multiply}\\\\\\62x=(43)(100)\\\\62x=4300\qquad\text{divide both sides by 62}\\\\x=\dfrac{4300}{62}\\\\x=\dfrac{4300:2}{62:2}\\\\x=\dfrac{2150}{31}\approx69.35[/tex]
[tex]\bold{METHOD\ 2:}\\\\p\%=\dfrac{p}{100}\to62\%=\dfrac{62}{100}=0.62\\\\62\%\ of\ x\ is\ equal\ to\ 43\to0.62x=43\qquad\text{divide both sides by 0.62}\\\\\dfrac{0.62x}{0.62}=\dfrac{43}{0.62}\\\\x=\dfrac{43\cdot100}{0.62\cdot100}\\\\x=\dfrac{4300}{62}\\\\x=\dfrac{2150}{31}\approx69.35[/tex]
