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Gibbons, small Asian apes, move by brachiation, swinging below a handhold to move forward to the next handhold. A 9.4 kg gibbon has an arm length (hand to shoulder) of 0.60 m. We can model its motion as that of a point mass swinging at the end of a 0.60-m-long, massless rod. At the lowest point of its swing, the gibbon is moving at 3.4 m/s . What upward force must a branch provide to support the swinging gibbon?

Respuesta :

Answer:

upward force acting = 261.6 N

Explanation:

given,

mass of gibbon = 9.4 kg

arm length = 0.6 m

speed of the swing

net force must provide

[tex]F_{branch} + F_{gravity}=F_{centripetal}[/tex]

force of gravity = - mg

[tex]F_{branch}=F_{centripetal}-F_{gravity}[/tex]

                        = [tex]\dfrac{mv^2}{r} + mg[/tex]

                        = [tex]m(\dfrac{3.4^2}{0.6} +9.8)[/tex]

                        =9 x 29.067

                        = 261.6 N

upward force acting = 261.6 N

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