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Three cars, X, Y, and Z, begin accelerating from rest at the same time. X is more massive than Y, and Y is more massive than Z. The net accelerating force exerted on each car is identical. After 30 seconds, which car has the most amount of momentum? A) They all have the same amount of momentum. B) Car X C) Car Y D) Car Z E) Cannot be determined based on the known information.

Respuesta :

Answer:car X

Explanation:  

Given

Three cars x,y and z begin accelerating from rest

mass of x is greater than y

mass of y is greater than z

[tex]m_x>m_y>m_z[/tex]

they all have same acceleration

after 30 sec

[tex]v=u+at[/tex]

[tex]v=0+a\times 30[/tex]

[tex]v=30 a[/tex]

All three have same final velocity thus Momentum of x

[tex]P_x=m_x\times 30a=30m_xa[/tex]

[tex]P_y=30m_ya[/tex]

[tex]P_z=30m_za[/tex]

thus Momentum of x is greater than y and z

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