Respuesta :
Answer:
58.44 C
Explanation:
Electric field is found by
[tex]E=\frac {\sigma}{\epsilon_o}=\frac {Q}{A\epsilon_o}[/tex]
Therefore, the charge is
[tex]Q=EA\epsilon_o [/tex]
[tex]Q= 4.00 ✕ 10^{6} N/C*1.65 *10^{6} m^{2}*8.854*10^{-12}= 58.4364 C [/tex]
Therefore, required charge is 58.44 C
The required charge would be [tex]58.41 \ C[/tex]
Define the electric field
Electric Field is a fundamental physical constant that is used to express the naturally occurring unit of electric charge which is [tex]1.602 \times0^{-19}coulombs.[/tex]
The expression for the electric field is,
[tex]E=\frac{\sigma }{\varepsilon _{0}}=\frac{Q}{A\varepsilon _{0}}\\[/tex]
[tex]Q=EA\varepsilon _{0}[/tex]
Now,
calculating the required charge as,
[tex]Q=\left ( 4\times 10^{6}N/c \right )\left ( 1.62 \ km^{2}\right )\left ( \frac{1000 m}{1km} \right )^{2}\left ( 8.85\times 10^{-12} \right )\\Q= 58.41 \ C[/tex]
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