The kinetic energy of boat A is nine times as much as the kinetic energy of boat B.
Explanation:
The kinetic energy of a body is the energy possessed by the body due to its motion, and it is given by:
[tex]K=\frac{1}{2}mv^2[/tex]
where
m is the mass of the body
v is its speed
In this problem, we have boat A and boat B.
Calling [tex]m_A[/tex] the mass of boat A and [tex]v_A[/tex] the speed of boat A, the kinetic energy of boat A is
[tex]K_A = \frac{1}{2}m_A v_A^2[/tex]
Calling [tex]m_B[/tex] the mass of boat B and [tex]v_B[/tex] the speed of boat B, the kinetic energy of boat B is
[tex]K_B = \frac{1}{2}m_B v_B^2[/tex]
We know that the two boats have same mass, so
[tex]m_A = m_B = m[/tex]
But the velocity of boat A is 3 times greater than that of boat B, so
[tex]v_A = 3 v_B[/tex]
So we can rewrite [tex]K_A[/tex] as
[tex]K_A = \frac{1}{2}m (3v_B)^2 = 9(\frac{1}{2}mv_B^2)=9K_B[/tex]
So, the kinetic energy of boat A is nine times as much as the kinetic energy of boat B.
Learn more about kinetic energy:
brainly.com/question/6536722
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