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Four members from a 45​-person committee are to be selected randomly to serve as​ chairperson, vice-chairperson,​ secretary, and treasurer. The first person selected is the​ chairperson; the​ second, the​ vice-chairperson; the​ third, the​ secretary; and the​ fourth, the treasurer. How many different leadership structures are​ possible?

Respuesta :

cjmejiab

Answer:

3575880

Step-by-step explanation:

We need to use Permutation method,

[tex]nPr= \frac{n!}{(n-r)!}[/tex]

Where n is the sample of size and r the combination considered, so

[tex]n=45\\r=4\\45P4= \frac{45!}{(45-4)!}\\45P4 = 3575880[/tex]

There is 3575880 possibilities to make leadership structures in that committee

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