a) mass of nylon 6,6 (15% yield) = 0.47 kg
b) Nylon 6 and Nylon 6,6 have different chemical structures so will have different physical properties.
Explanation:
a) First we need to calculate the number of moles of adipic acid and hemetylenediamine.
number of moles = mass / molecular weight
number of moles of adipic acid = 2 / 146 = 0.0137 kmoles = 13.7 moles
number of moles of hemetylenediamine = 4.5 / 116 = 0.0389 kmoles = 38.9 moles
We see from the chemical reaction (see attached picture) that n moles of adipic acid will react with n moles of hemetylenediamine to produce the Nylon 6,6 and (2n-1) water moles.
From our data 13.7 moles of adipic acid will react with 13.7 moles of hemetylenediamine o produce the Nylon 6,6 and (2×13.7-1) water moles.
For a theoretical 100% yield mass of nylon 6,6 will be:
mass of nylon 6,6 = mass of reacted adipic acid + mass of reacted hemetylenediamine - mass of water
mass of reacted adipic acid = 2 kg
mass of reacted hemetylenediamine = number of moles × molecular weight
mass of reacted hemetylenediamine = 13.7 × 116 = 1589.2 g = 1.59 kg
mass of water = number of moles × molecular weight
mass of water = (2×13.7-1) × 18 = 475.5 g = 0.48 kg
mass of nylon 6,6 = 2 + 1.59 - 0.48 = 3.11 kg
Now if the yield of the reaction is 15% only 15% of the nylon 6,6 quantity will be produced:
mass of nylon 6,6 (15% yield) = (15 / 100) × 3.11 = 0.47 kg
b) You may find the chemical diagrams of Nylon 6 and Nylon 6,6 in the attached picture. They have different chemical structures. This will result in different physical properties.
density of nylon 6 = 1.084 g/mL
density of nylon 6,6 = 1.314 g/mL
melting point of nylon 6 = 220 °C
melting point of nylon 6,6 = 264 °C
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