Answer:
the grating space is given as
[tex]a = 3.43 \times 10^{-6} m[/tex]
Explanation:
As we know that the angular position of first order maximum is given as
[tex]a sin\theta = \frac{3}{2}\lambda[/tex]
so we will have
[tex]\theta = \frac{27}{2}[/tex]
[tex]\theta = 13.5 degree[/tex]
so we have
[tex]a = \frac{3\lambda}{2sin\theta}[/tex]
[tex]a = \frac{3(534 nm)}{2 sin13.5}[/tex]
[tex]a = 3.43 \times 10^{-6} m[/tex]
So the grating space is given as
[tex]a = 3.43 \times 10^{-6} m[/tex]