Answer:
Angular velocity will be 1.525 rad/sec
Explanation:
We have given radius of the circular path r = 8 m
We have given centripetal acceleration [tex]\alpha =1.9g=1.9\times 9.8=18.62m/sec^2[/tex]
Now we know that centripetal acceleration is given by [tex]\alpha =\frac{v^2}{r}[/tex], here v is linear velocity and r is radius
So [tex]18.62 =\frac{v^2}{8}[/tex]
v = 12.204 m/sec
Now we know that linear velocity is given by [tex]v=\omega r[/tex], here [tex]\omega[/tex] is angular velocity and r is radius
So [tex]\omega =\frac{v}{r}=\frac{12.20}{8}=1.525rad/sec[/tex]
