Garnation
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​Claim: The mean pulse rate​ (in beats per​ minute) of adult males is equal to 69 bpm. For a random sample of 171 adult​ males, the mean pulse rate is 67.6 bpm and the standard deviation is 11.1 bpm. Find the value of the test statistic.

Respuesta :

opudodennis

Answer:

-1.649313114

Step-by-step explanation:

Sample size, n=171

Sample mean, x=67.6

Standard deviation, s=11.1

Study claims mean pulse [tex]\mu=69[/tex]

Null hypothesis

[tex]H_0: \mu=69[/tex]

[tex]H_a: \mu \neq 69[/tex]

Test statistic is given by

[tex]t=\frac {x-\mu}{\frac {s}{\sqrt n}}[/tex] hence  

[tex]t=\frac {67.6-69}{\frac {11.1}{\sqrt 171}}=-1.649313114[/tex]

The test static value is -1.649313114

ashishdwivedilVT

The value of the test statistic for the given data comes to be -1.6493.

Mean pulse rate (in beats per​ minute) of adult males μ= 69 bpm

Sample size N = 171

Mean of sample X = 67.6 bpm

Standard deviation σ= 11.1 bpm

What is a test statistic?

A test statistic is a statistical inference used to determine whether a particular data support a hypothesis or not.

The value of test statistic = (X-μ)/(σ/√N)

The value of test statistic = (67.6-69)/(11.1/√171)

The value of test statistic = -1.6493

Therefore, The value of the test statistic for the given data comes to be -1.6493.

To get more about test statistics visit:

https://brainly.com/question/159804933

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