Answer:
-0.1 Joules
Explanation:
Here, the kinetic energy of the spring and glider is conserved.
So, we get
KE of spring + Work done by friction = Change in momentum of glider
[tex]\frac{1}{2}k(x_f^2-x_i^2)+W_f=\frac{1}{2}m(v^2-u^2)\\\Rightarrow W_f=\frac{1}{2}m(v^2-u^2)-\frac{1}{2}k(x_f^2-x_i^2)\\\Rightarrow W_f=\frac{1}{2}0.4(1^2-0^2)-\frac{1}{2}20(0.2^2-0.1^2)\\\Rightarrow W_f=-0.1\ Joules[/tex]
The work done by friction during that segment of motion is -0.1 Joules