What will be printed after the following code is executed? String str = "abc456"; int m = 3; while ( m =< str.length() - 1) { if (Character.isDigit(str.charAt(m))) System.out.print(Character.toUpperCase(str.charAt(m))); m++; }

while loop will run till the condition is true that given value for m is greater than or equal to (string length -1) or say 5
As m = 3 is given so first time the loop will run it goes to if statement which uses m value as a index to pull character from str and checks if it is a digit or alphabet. It will proceed if the character is a digit.
As at index 3 (starting from 0) the character is 4, so it will proceed to next statement which prints the extracted character on the screen after converting it into Upper case.
As digits are not affected so the digit 4 will be printed.
m will be increased by 1 making m = 4.
Now the while condition is still true so is statement will return character at index 4 that is 5.
It will be sent to next statement but toUpperCase function does not changes digits so 5 will be printed.
Increment in m makes m = 5
While statement is still true so 5th character from string is extracted that is 6. As it is a digit so moving to next statement will not change the character because toUpperCase does not apply on digits.
Now when m is incremented it becomes 6 which will give false to the while condition so the loop will be terminated.
Now the answer printed on to screen in 456.

I hope it will help you!

stigawithfun stigawithfun · Answer 2 · 2019-11-06T20:00:56+01:00

Answer:

456 will be printed

Explanation:

The following shows a well formatted equivalent of the code snippet:

String str = "abc456"; //Line 1

int m = 3; //Line 2

while (m <= str.length() - 1) { //Line 3

if (Character.isDigit(str.charAt(m))) //Line 4

System.out.print(Character.toUpperCase(str.charAt(m))); //Line 5

m++; //Line 6

} //Line 7

Line 1 shows the declaration and initialization of a String variable str.

Line 2 shows the declaration and initialization of an integer variable m.

Lines 3 through 7 show a while loop.

The loop starts at m = 3, increments m by one at every cycle, and ends at m = 5 which is one less than the length of the String str. i.e 6 - 1 = 5

At each cycle, the loop checks if the character at index m of the str is a digit. If it is a digit, it is converted to an uppercase letter(which is irrelevant) and then printed to the console.

At m=3, the character is a digit which is 4

At m=4, the character is a digit which is 5

At m=5, the character is a digit which is 6

Therefore, 456 is printed to the console.

Note: I have assumed that the statement in the while loop of the code you wrote was a typo and as such I have changed it to the correct syntax. That is, I have changed ;

while(m =< str.length( ) - 1) to

while(m <= str.length( ) - 1) for the code to perform the intended function.

Otherwise, if it is the case that it wasn't a typo, then the code will neither compile nor run as it contains a syntax error.

Hope this helps!