A car is traveling with a speed of 23.0 m/s along a straight horizontal road. The wheels have a radius of 0.310 m. If the car speeds up with a linear acceleration of 1.30 m/s2 for 8.60 s, find the angular displacement of each wheel during this period.

Respuesta :

Answer:

656.09rad

Explanation:

We start from the equation of time based on the acceleration that says the following

[tex]x(t)= \frac{1}{2}at^2+v_0t+x_0[/tex]

We have this values practically,

[tex]v_0=23m/s \\t=8.60s\\a=1.3m/s^2\\x_0 = 0m[/tex]

Substituting,

[tex]x(8.6) = \frac{1}{2}(1.3)(8.6)^2+(23)(8.6)+0\\x(8.6)=203.39m[/tex]

Angular velocity is given by,

[tex]d_{\theta}=2\pi*(\frac{d}{2\pi r}) =\frac{d}{r} = \frac{203.39}{0.310} = 656.09rad[/tex]

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