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A 1.38 kg piece of cheese is placed on a vertical spring of negligible mass and force constant k = 2600 N/m that is compressed 17.4 cm. Part A When the spring is released, how high does the cheese rise from this initial position? (The cheese and the spring are not attached.)

Respuesta :

Answer:

y=1.72m

Explanation:

onyebuchinnaji

The height attained by the cheese when released is 2.91 m.

The given parameters;

  • mass of the cheese, m = 1.38 kg
  • spring constant, k = 2600 N/m
  • extension of the spring, x = 17.4 cm = 0.174 m

The height attained by the cheese when released is determined by applying the principle of conservation of energy as shown below;

P.E = Ux

mgh = ¹/₂kx²

[tex]h = \frac{kx^2}{2mg} \\\\h = \frac{2600 \times (0.174)^2}{2 \times 1.38 \times 9.8} \\\\h = 2.91 \ m[/tex]

Thus, the height attained by the cheese when released is 2.91 m.

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