Respuesta :
Explanation:
The given data is as follows.
q = 69.0 kJ = 69000 J (as 1 kJ = 1000 J),
mass (m) = 8.10 kg = 8100 g (as 1 kg = 1000 g)
[tex]T_{i} = 33.9^{o}C[/tex] = (33.9 + 273) K = 306.9 K
C = 4.18 J/gK
As we know that the relation between heat and change in temperature is as follows.
q = [tex]m \times C \times \Delta T[/tex]
Putting the values into the above formula to calculate the final temperature as follows.
q = [tex]m \times C \times \Delta T[/tex]
69000 J = [tex]8100 g \times 4.18 J/g K \times (T_{f} - 306.9 K)[/tex]
69000 J = [tex]33858 \times (T_{f} - 306.9 K)[/tex]
[tex](T_{f} - 306.9 K)[/tex] = 2.037 K
[tex]T_{f}[/tex] = (2.037 + 306.9) K
= 308.9 K
or, = 309 K (approx)
Thus, we can conclude that the new temperature of the water bath is 309 K.
The new temperature of the water bath is 309 K.
What is the specific heat?
In a chemical reaction, The specific heat is the quantity of heat needed to change the temperature of 1 kg of mass by 1 ° C.
It can be expressed by the formula:
Q = mcΔT
From the parameters given:
- The mass of the water bath = 8.10 kg = 8100 g
- The temperature of the water bath = 33.9 ° C = (273 + 33.9) K = 306.9 K
- The specific heat = 69.0 kJ = 69000 J
Using the relation of the specific heat:
Q = mcΔT
69000 J = 8100 g × 4.18 J/gK × (T₂ - T₁)
69000 J = 8100 g × 4.18 J/gK × (T₂ - 306.9 K)
T₂ = 308.9 K
T₂ ≅ 309 K
Therefore, we can conclude that the new temperature of the water bath is 309 K.
Learn more about specific heat here:
https://brainly.com/question/10219465
