Answer:
Rotational kinetic energy is 0.513 j
Transnational kinetic energy is 172.8 j           Â
Explanation:
We have given mass of the baseball m = 0.15 kg
radius r = 3.7 cm = 0.037 m
Angular velocity is given as [tex]\omega =50rad/sec[/tex]
Linear velocity v = 48 m/sec
We know that moment of inertia is given by [tex]I=\frac{1}{2}mr^2=\frac{1}{2}\times 0.15\times 0.037^2=1.026\times 10^{-4}kgm^2[/tex]
Now rotational kinetic energy is given by
[tex]KE_{rotational}=\frac{1}{2}\times 1.026\times 10^{-4}\times 50^2=0.513j[/tex]
Now transnational kinetic energy is given by [tex]KE_{translational}=\frac{1}{2}mv^2=\frac{1}{2}\times 0.15\times 48^2=172.8j[/tex]