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Consider the roots of a cubic equation with integral coefficients:-1, and -2. The root -1 has a multiplicity of 2. Which choice is
the cubic equation?

Respuesta :

Answer:

The equation is,

[tex](x+1)^{2} \times (x+2) = 0[/tex]

Step-by-step explanation:

According to the question, the equation is cubic and have roots -1 (with multiplicity of 2) and -2.

So, the equation is,

[tex](x+1)^{2} \times (x+2) = 0[/tex]

[Since, when a , b , c are the roots of a cubic equation, the equation is

given by [tex](x-a) \times (x-b) \times (x-c) = 0[/tex] ]

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