Answer:
The equation is,
[tex](x+1)^{2} \times (x+2) = 0[/tex]
Step-by-step explanation:
According to the question, the equation is cubic and have roots -1 (with multiplicity of 2) and -2.
So, the equation is,
[tex](x+1)^{2} \times (x+2) = 0[/tex]
[Since, when a , b , c are the roots of a cubic equation, the equation is
given by [tex](x-a) \times (x-b) \times (x-c) = 0[/tex] ]