Answer:
Fe is the limiting reactant and 1.75 mol of Fe₂O₃ can be produced.
Explanation:
The equation for the reaction is;
4 Fe(s) + 3 O2(g) → 2 Fe2O3(s)
Therefore, 4 moles of Iron reacts with 3 moles of Oxygen to form 2 moles of iron (iii) oxide.
We are given;
3.5 moles of Fe and 3 moles of Oxygen gas
- But, mole ratio of Fe to O₂ is 4 : 3
- From the ratio, 3.5 moles of Fe will require 2.625 moles of O₂, while 3 moles of Oxygen would require 4 moles of Fe.
- Therefore, oxygen gas is in excess and thus Iron is the rate limiting reactant.
- Therefore, 3.5 moles of Fe would require 2.625 moles (3.5 mol × 3/4) of oxygen to form 1.75 moles (3.5 mol × 2/4) of Fe₂O₃
Thus, we will be correct to say that, Fe is the limiting reactant and 1.75 mol of Fe₂O₃ can be produced.
