For this case we must find an expression equivalent to:
[tex](x ^ 2-3x) (4x ^ 2 + 2x-9) =[/tex]
We apply distributive property, term by term, taking into account that:[tex]- * + = -\\- * - = +\\x ^ 2 * 4x ^ 2 + x ^ 2 * 2x-x ^ 2 * 9-3x * 4x ^ 2-3x * 2x + 3x * 9 =[/tex]
By definition we have to, to multiply powers of the same base, the same base is placed and the exponents are added:
[tex]4x ^ 4 + 2x ^ 3-9x ^ 2-12x ^ 3-6x ^ 2 + 27x =[/tex]
We add similar terms taking into account that:
Equal signs are added and the same sign is placed.
Different signs are subtracted and the major sign is placed.
[tex]4x ^ 4-10x ^ 3-15x ^ 2 + 27x[/tex]
Answer:
An equivalent expression is: [tex]4x ^ 4-10x ^ 3-15x ^ 2 + 27x[/tex]