A car traveling at 54km/hr slows down uniformly to a velocity of 18km/hr when the break was gradually applied then it would take 5 s to cover a distance of 50m and the deceleration would be 2 m/s².
What is acceleration?
The rate of change of the velocity with respect to time is known as the acceleration of the object.
As given in the problem a car traveling at 54km/hr slows down uniformly to a velocity of 18km/hr when the break were gradually applied
By using the third equation of motion
v² - u² = 2×a×s
First, convert velocities in m/s units
54 km/hr = 54 ×1000/3600 m/s
= 15 m/s
18km/hr =18 ×1000/3600 m/s
= 5 m/s
By substituting the respective values in the equation , as given the car cover a distance of 50m
v² - u² = 2×a×s
5²-15² =2×a×50
a = -2 m/s²
Now using the first equation of motion
v = u + at
5 = 15 + -2×t
t = 5 s
Thus, it would take 5 s to cover a distance of 50m and the deceleration would be 2 m/s².
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