An animal cell with a solute potential of -1.2 bars is placed into an open beaker containing a solution with a solute potential of -3.8 bars. What is the resulting movement of water in this example? A) Water will move into the cell because the solution is hypotonic to the cell. B) Water will not move into nor out of the cell because the solution and the cell are isotonic. C) Water will move out of the cell because the beaker solution has a lower water potential than the cell. D) Water will move into the cell because the cell has a higher water potential than the solution in the beaker.