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04-11-2019
Mathematics

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Write an equation passing through point A(6,-1) that is perpendicular y= -2x+8

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cinderofsoulsss cinderofsoulsss

04-11-2019

The slope perpendicular to y = -2x + 8 is [tex]\frac{1}{2}[/tex]

Point slope form (y = a(x - h) + k):

y = [tex]\frac{1}{2}[/tex](x - 6) - 1

Slope intercept form (y = mx + b):

y = [tex]\frac{1}{2}[/tex]x - 4

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