The clam in free fall was dropped from 44.1 m above the ground.
Explanation:
To find how high the clam was dropped from, we just need to analyze its vertical motion.
Its vertical motion is a free-fall motion: this means that the only force acting on the clam is gravity, so it falls down at a constant acceleration of
[tex]g=9.8 m/s^2[/tex]
known as the acceleration of gravity.
We can find the vertical distance covered by the clam by using the following suvat equation:
[tex]s=ut+\frac{1}{2}at^2[/tex]
where
u = 0 is the initial vertical velocity of the clam (zero since the seagull is flying horizontally)
t = 3.0 s is the time taken for the fall
[tex]a=9.8 m/s^2[/tex] is the acceleration
Solving for s, we find
[tex]s=0+\frac{1}{2}(9.8)(3.0)^2=44.1 m[/tex]
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