solving inequalities for word problems:
twice a number plus 10 is greater than three times that number less 4. what is the number?

Respuesta :

For this case we have to:

x: Let the variable representing the unknown number

We algebraically rewrite the given expression:

Twice a number plus 10, is represented as:[tex]2x + 10[/tex]

Three times that number less 4. is represented as:

[tex]3x-4[/tex]

Thus, the complete expression is:

[tex]2x + 10> 3x-4[/tex]

Subtracting 3x from both sides of the inequality:

[tex]2x-3x + 10> -4\\-x + 10> -4[/tex]

Subtracting 10 from both sides of the inequality:

[tex]-x> -4-10[/tex]

Equal signs are added and the same sign is placed:

[tex]-x> -14[/tex]

We multiply by -1 on both sides, taking into account that the sense of inequality changes:

[tex]x <14[/tex]

The solution is given by all values of "x" less than 14.

Answer:

[tex]x <14[/tex]

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