Given P(A) = 0.072, P(B) = 0.180, and P(C) = 0.027, and that events A, B, and C are mutually exclusive,then P(A or B or C) is 0.279
Solution:
Given that probability of event A is P(A) = 0.072
Probability of event B is P(B) = 0.180
Probability of event C is P(C) = 0.027
Also event A, B and C are mutually exclusive.
Need to determine P( A or B or C )
For mutually exclusive events
P( A or B or C ) = P(A) + P(B) + P(C)
= 0.072 + 0.180 + 0.027 = 0.279
Hence probability of occurrence of event A or event B or event C , where A , B and C are mutually exclusive events is 0.279.
