For this case we have the following equation:
[tex]x ^2 = \frac{36}{81}[/tex]
We must clear the value of the variable "x", to do this, we apply square root to both sides of the equation:
[tex]x = \pm \sqrt {\frac {36} {81}}[/tex]
Thus, we have two roots:
[tex]x_ {1} = \sqrt {\frac {36} {81}} = \frac {6} {9} = \frac {2} {3}\\x_ {2} = - \sqrt {\frac {36} {81}} = - \frac {6} {9} = - \frac {2} {3}[/tex]
Answer:
[tex]x_ {1} =\frac {2} {3}\\x_ {2} =- \frac {2} {3}[/tex]
