Respuesta :

[tex]\boxed{91mm<433cm<133dm<308km}[/tex]

Explanation:

First of all, let's transform each measurement into meter knowing the following relationships:

[tex]1dm=0.1m \\ \\ 1cm=0.01m \\ \\ 1km=1000 m \\ \\ 1mm=0.001m[/tex]

Therefore, we can compute the following:

[tex]\bullet \ 133dm \rightarrow 133dm(\frac{0.1m}{1dm})=13.3m \\ \\ \bullet \ 433cm \rightarrow 433cm(\frac{0.01m}{1cm})=4.33m \\ \\ \bullet \ 308km \rightarrow 308km(\frac{1000m}{1km})=308,000m \\ \\ \bullet \ 91mm \rightarrow 91mm(\frac{0.001m}{1mm})=0.091m[/tex]

Writing this in increasing order:

[tex]0.091m<4.33m<13.3m<308,000m \\ \\ Or: \\ \\ \boxed{91mm<433cm<133dm<308km}[/tex]

Learn more:

jovian planets in order of increasing distance from the Sun: https://brainly.com/question/12534549

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