An object, which is initially at rest, accelerates at a rate of 10 m/s2 . Its final position is 85 m from its initial position at the end of that acceleration. For how much time did it accelerate?

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Answer:

4.12 seconds

Explanation:

From the kinetic equation

[tex]s=ut+0.5at^{2}[/tex] where s is the displacement, u is initial velocity, t is time of travel and a is acceleration.

Since the object is initially at rest, the initial velocity is zero hence the equation can be re-written as

[tex]s=0.5at^{2}[/tex] and making t the subject of the formula

[tex]t=\sqrt {\frac {2s}{a}}[/tex]

Substituting s for 85 m and a for 10 m/s2

[tex]t=\sqrt {\frac {2*85 m}{10}}=4.123105626 s[/tex]

Therefore, time is approximately 4.12 seconds

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