Respuesta :

Neetoo

Answer:

V₂ = 9.2 L

Explanation:

Initial volume = 2.3 L

initial temperature = 150 K

Initial pressure = 15 psi

Final temperature = 300 K

Final pressure = 7.5 psi

Final volume = ?

Solution:

P₁V₁/T₁ = P₂V₂/T₂

V₂ = P₁V₁T₂ /T₁ P₂

V₂= 15 psi × 2.3 L × 300 K / 150 K × 7.5 psi

V₂  =10350 psi .L.  K  / 1125 K .psi

V₂ = 9.2 L

sebassandin

Answer:

[tex]V_2=9.2L[/tex]

Explanation:

Hello,

In this case, in terms of the combined ideal gas law:

[tex]\frac{p_1V_1}{T_1}= \frac{p_2V_2}{T_2}[/tex]

The volume at the second state turns out:

[tex]V_2=\frac{p_1V_1T_2}{T_1p_2}= \frac{15psi*2.3L*(2*150K)}{150K*(15psi/2)} =9.2L[/tex]

Best regards.

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