Answer:
Step-by-step explanation:
[tex]sec^2\theta-tan^2 \theta=1\\\frac{42}{36} -tan^2\theta=1\\tan^2 \theta=\frac{42}{36}-1=\frac{6}{36}\\as~ sec~ \theta ~is~positive~and ~sin~\theta~is ~negative.\\\theta~lies~in~4th~quadrant.\\tan~\theta~is~negative.\\tan~\theta=\frac{1}{\sqrt{6} }[/tex]
