Answer:
[tex](F\cdot \: P)(10)=94640[/tex]
Step-by-step explanation:
By algebraic property of functions we have;
[tex](F\cdot \: P)(y) = F(y) \cdot \: P(y)[/tex]
This implies that,
[tex](F\cdot \: P)(10) = F(10) \cdot \: P(10)[/tex]
But
[tex] F(y) = 8y + 11[/tex]
[tex] \implies \: F(10) = 8 \times 10 + 11 =80 + 11 = 91[/tex]
and
[tex] P(y) = {y}^{3} + 4y[/tex]
[tex]P(10) = {10}^{3} + 4 \times 10 = 1000 + 40 = 1040[/tex]
Therefore,
[tex](F\cdot \: P)(10) = 91 \times 1040 = 94640[/tex]
