The percentage of the adult racehorses weigh more than 570 kg is
1.7% ⇒ 1st answer
Step-by-step explanation:
Adult racehorse weights are normally distributed, with a mean of
500 kg and a standard deviation of 33 kg
We need to find the percentage of the adult racehorses weigh more
than 570 kg
To solve the problem do these steps
1. Find z-score
2. Use z-score to find the corresponding area which represented P(x)
3. Change P(x) to percentage
∵ z = (x - μ)/σ
∵ The mean μ = 500 kg
∵ The standard deviation σ = 33 kg
∵ x = 570 kg
Substitute these values in the rule above
∴ z = [tex]\frac{570-500}{33}=2.12[/tex]
Let us use the normal distribution table to find the corresponding area
∵ The area corresponding to z-score of 2.12 is 0.98300
∵ We need x > 570 , then we need the area to the right of the z-score
∴ P(x > 570) = 1 - 0.98300 = 0.017
Change it to percentage by multiplying the answer by 100%
∴ The percentage of x > 570 = 0.017 × 100% = 1.7%
The percentage of the adult racehorses weigh more than 570 kg is
1.7%
Learn more:
You can learn more about the normal distribution curve in brainly.com/question/6073431
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