Answer:
[tex]y = \frac{1}{2}x - 6[/tex]
Step-by-step explanation:
Slope of line (m) = 1/2
Since the line is passing through the point (6, -3) ∴ [tex]x_{1} = 6\ and\ y_{1} = -3[/tex]
Now, equation of line in Point-slope form is:
[tex](y - y_{1}) = m (x - x_{1})[/tex]
By substituting the values of m, [tex]x_{1}\ and\ y_{1}[/tex]
[tex](y - (3)) = \frac{1}{2}(x - 6)[/tex]
[tex]y + 3 = \frac{1}{2} ( x - 6)[/tex]
[tex]y = \frac{1}{2}x - 3 - 3[/tex]
[tex]y = \frac{1}{2}x - 6[/tex]
Therefore, the equation of line passing through pong (6, -3) is [tex]y = \frac{1}{2}x - 6[/tex]
