Triangle A C B is shown. Angle A C B is a right angle. Altitude h is drawn from point C to point D on side A B, forming a right angle. Side A C is labeled b and side C B is labeled a. The length of A D is 6 and the length of side D B is 14. Use the geometric mean (leg) theorem. What is the value of a? 7 StartRoot 2 EndRoot 2 StartRoot 70 EndRoot 20 StartRoot 5 EndRoot 70 StartRoot 5 EndRoot

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Answer:

Answer B.) [tex]\sqrt[2]{70}[/tex]

As per the geometric mean theorem of a triangle, the value of 'a' is 2√(70).

What is the geometric mean theorem of a triangle?

"The geometric mean theorem describes a relation between the altitude on the hypotenuse in a right triangle and the two line segments it creates on the hypotenuse. It states that the geometric mean of the two segments equals the altitude."

Given, AC = b, CA = a, CD = h.

The hypotenuse has two sections AD and DB.

AD = 6, DB = 14

Therefore, in triangle ABC:

(CD)² = AD × DB

⇒ CD² = (AD × DB)

⇒ CD² = (6 × 14)

⇒ CD² = 84

Now, ΔBCD is also a right angle triangle.

Therefore, (BC)² = (CD)² + (DB)²

⇒ a² =  84 + (14)²

⇒ a² = 280

⇒ a = 2√(70)

Learn more about the geometric mean theorem of a triangle here: https://brainly.com/question/24095553

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