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what is the focal length of a concave mirror that magnifies, by a factor of +3.2, an object that is placed 30 cm from the mirror?

A. 23cm
B. 32cm
C. 44cm
D. 46cm

Respuesta :

Answer:

C. 44 cm

Explanation:

We can solve the problem by using the lens equation:

[tex]\frac{1}{f}=\frac{1}{p}+\frac{1}{q}[/tex]

where

f is the focal length

p = 30 cm is the distance of the object from the mirror

q is the distance of the image from the mirror

We also know that the magnification is

[tex]M=-\frac{q}{p}=+3.2[/tex]

So

[tex]q=-3.2p=-3.2(30)=-96 cm[/tex]

Substituting into the first equation, we find f:

[tex]\frac{1}{f}=\frac{1}{30}-\frac{1}{96}=0.0229 cm^{-1} \rightarrow f=43.7 cm \sim 44 cm[/tex]

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