Answer: 10/12
Step-by-step explanation: A die has 6 sides, so if the probability is that two dice are rolled, you would count 6 two time, which would be 12. The lower half would then automatically become 12. Seeing as the probability you could get a 3 rolling a 6 sided die 2 times is 2, that is the upper half. so in conclusion, the answer would be 2/12.
The probability that neither die shows a 3 on it is 25/36
Probability is the likelihood or chance that an event will occur
Probability = Expected Outcome/Total outcome
If two dice are rolled, the toral outcome will be 6^2 = 36
If a 3 will show, the required events will be (3, 1), (1, 3) (3, 2), (2, 3), (3, 3), (3, 4), (4, 3), (3, 5), (5, 3) (3, 6) and (6, 3)
The expected outcome = 11
Pr (either a 3 will show) = 11/36
Pr(neither a 3 will show on a die) = 1 - 11/36 = 25/36
Hence the probability that neither die shows a 3 on it is 25/36
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