Respuesta :
Answer:
1. no solutions
2. one solution
Step-by-step explanation:
1. -4(5-3x)=12x+20
-20+12x=12x+20
-40+12x=12x
-40=0?????
So no solutions.
2. 3x+7(x+1)=2(6x+5)+2
3x+7x+7=12x+10+2
10x+7=12x+12
-2x+7=12
-2x=5
x=-5/2
So one solution.
Answer:
The answers are:
1. No solution.
2. One solution: [tex]x=-\frac{1}{2}[/tex]
Step-by-step explanation:
In order to determine the solutions for both equations, we have to solve every one. In any equation of one variable, we could get three types of solution:
- One solution. The variable has a unique value.
- No solution. The equality is not fulfilled.
- Infinite solution. The variable is eliminated from the equation and the equality is fulfilled.
So, solving both equation:
1.-
[tex]-4(5-3x)=12x+20\\-20+12x=12x+20\\12x-12x=20+20\\0=40\\[/tex]
The equality is not fulfilled. There is not solution.
2.-
[tex]3x+7(x+1)=2(6x+5)-2\\3x+7x+7=12x+10-2\\10x-12x=8-7\\-2x=1\\x=-\frac{1}{2}[/tex]
There is one solution. [tex]x=-\frac{1}{2}[/tex]
Finally, the answers for both questions are:
1. No solution.
2. One solution: [tex]x=-\frac{1}{2}[/tex]