Answer:
[tex]\left \| F \right \| = 42.3 N[/tex]
[tex]\theta = 11.7[/tex] degree north of west
Explanation:
Given data:
Force by trout 150 N
Force by Ohtani 100 N
Force by pujols 200 N
Net force is given as
[tex]F = 150 j - 200\times cos 45j + ( 100i - 200\times sin45 i)[/tex]
[tex]F = (100 - 100\sqrt {2}) i + (150 - 100\sqrt{2}) j[/tex]
[tex]\left \| F \right \| = \sqrt{(100 - 100\sqrt{2})^2 + (150 -100\sqrt{2})^2}[/tex]
[tex]\left \| F \right \| = 42.3 N[/tex]
Direction is
[tex]tan\theta = \left | \frac{150-100\sqrt{2}}{100-100\sqrt{2}} \right |[/tex]
[tex]\theta = 11.7[/tex] degree north of west
