Answer:
answered θ=40.52°
Step-by-step explanation:
We know that
S= 2300m , u= 252 m/s, a=9.8 m/s^2
s= u×t +1/2at^2
putting values we get
-2300= -252sin30°×t+ 0.5(-9.8)t^2
4.9t^2+126t-2300=0
⇒t= 12.33 sec
Horizontal distance traveled = 252×12.33cos30°
=2690.87 m
therefore the angle θ is [tex]\tan^{-1} \frac{2300}{2690.87}[/tex]
⇒ θ= 40.52°
