Answer:
[tex]9.09*10^{21} molecules O_2[/tex]
Explanation:
The formula for Mercury(II) Oxide is [tex]HgO[/tex]
Balanced Equation: [tex]2HgO = 2Hg + O_2[/tex]
Stoichiometry: [tex](6.54g HgO)*(\frac{1molHgO}{216.59gHgO})*(\frac{1molO_2}{2molHgO})*(\frac{6.02*10^{23}molecules O_2}{1molO_2})= 9.09*10^{21}moleculesO_2[/tex]