Answer:
The maximum acceptable price would be $16.24
Explanation:
In order to solve this problem we have to create an equation, and equalize both prices, so the price of the filter will be expressed by "y".
We know that the X filter costs $5 and must be changed every 9,000 miles, with the oil 5 quartz, and one quart of oil must be added every 500 miles, the resultant equation for the price of those 9,000 miles is:
[tex]\frac{5+ 5(1.09)+16(1.09)}{9000}[/tex]
And to express the new oil it would be:
[tex]\frac{x+ 5(1.09)+}{7000}[/tex]
So we just have to equalize them:
[tex]\frac{x+ 5(1.09)+}{7000}=\frac{5+ 5(1.09)+16(1.09)}{9000}\\9000x+49,050=195,230\\9000x=195,230-49,050=146,180\\x=\frac{146180}{9000} \\x= 16.2422[/tex]
So we know that the maximum price that the new oil filter would be $16.2422 because at that point it costs the same as the other filter witht he cost of the adding of the oil quarts.